How do you simplify $(2 a^{- 3}) {(a^{7} b^{- 1})}^{3}$ $(2a^-3)(a^7b^-1)^3$ ?

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Answer 1 · 2017-06-19T21:03:49

The answer is $\frac{2 a^{18}}{b^{3}}$ $(2a^18)/b^3$ . See the process below!

1. Distribute the exponent of 3 - multiply every exponent inside the parentheses by 3.

$(2 a^{- 3}) (a^{21} b^{- 3})$ $(2a^-3)(a^21b^-3)$

2. Simplify by multiplying the same factors together.
Remember, when multiplying powers with the same base, you add the exponents.

$2 a^{18} b^{- 3}$ $2a^18b^-3$

We should give answers with positive indices. So now

$\frac{2 a^{18}}{b^{3}}$ $(2a^18)/b^3$

That's your final answer!

How do you simplify (2a^-3)(a^7b^-1)^3(2a−3)(a7b−1)3 (2a^-3)(a^7b^-1)^3?