How do you solve $\sqrt{x + 7} = 2 \sqrt{x}$ $sqrt( x + 7) = 2 sqrtx$ ?

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Answer 1 · 2017-06-29T10:01:01

Get rid of the square roots.

${(\sqrt{x + 7})}^{2} = {(2 \sqrt{x})}^{2}$ $(sqrt(x+7))^2= (2sqrtx)^2$

$x + 7 = 4 x$ $x+7=4x$

$3 x = 7$ $3x=7$

$x = \frac{7}{3}$ $x=7/3$

Answer 2 · 2017-06-29T10:03:07

The answer is $\frac{7}{3}$ $7/3$ .

$\sqrt{x + 7}$ $sqrt (x+7)$ = 2 $\sqrt{x}$ $sqrtx$

${(\sqrt{x + 7})}^{2}$ $(sqrt (x+7))^2$ = ${(2 \sqrt{x})}^{2}$ $(2 sqrtx)^2$

$x + 7$ $x + 7$ = $4 x$ $4x$

$7$ $7$ = $4 x - x$ $4x - x$

$7 = 3 x$ $7 = 3x$

$x = \frac{7}{3}$ $x = 7/3$

How do you solve √x+7=2√xsqrt( x + 7) = 2 sqrtx?