How do you simplify #(-6+5i)(7-5i)(6+6i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Καδήρ Κ. Jul 21, 2017 #-102(1+i)# Explanation: #(-6+5i)(7-5i)(6+6i)=# #(-42+30i+35i-25i^2)(6+6i)=# #(-42+65i+25)(6+6i)=# #(-17+65i)(6+6i)=# #(-102-102i+390+390i^2)=# #-102(1+i)# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 1719 views around the world You can reuse this answer Creative Commons License