Question

What is the vertex form of `y= (x+6)(x-23)`?

Answer 1

`(x-17/2)^2-825/4`

And the vertex is the point `A(17/2,825/4)`

Explanation:

`y=(x+6)(x-23)=x^2-17x-138=`

`x^2-2*17/2x-138=x^2-2*17/2x+(17/2)^2-(17/2)^2-138=`

`(x-17/2)^2-825/4`

And the vertex is the point `A(17/2,825/4)`