Question

How do you find the area of `triangle ABC` given b=14.6, c=12.8, `mangleA=56`?

Answer 1

`77.5`

Explanation:

`"Area of non right-angled triangle" = (a*b*sinC)/2`, where:
`a = 14.6`
`b=12.8`
`C=56`

`(12.8*14.6*sin(56^circ))/2=77.4652708~~77.5`