How do you sketch the graph of y=-(x+2)^2-2 and describe the transformation?

1 Answer
Aug 8, 2017

The graph of y=-(x+2)^2-2 is:

graph{-(x+2)^2-2 [-10, 10, -5, 5]}

Its transformation is a reflection over the x-axis, a translation of 2 units left and a translation of 2 units down.

Explanation:

Have a look at the following summary for transformation rules of graphs:

![http://www.onlinemathlearning.com/http://horizontal-vertical-stretch.html](https://useruploads.socratic.org/uQFLN3t1QTWS2uRsX2qF_transformation-rules-graphs.png)

Transformations are called transformations because they start off with the "original" or "standard" function f(x) and then move/transform it to a different point based on a variety of things being added to the function or multiplied to it.

The original function in this case is f(x)=x^2. Let's graph this first to see how the translations affect it:

graph{x^2 [-10, 10, -5, 5]}
We notice that it has 3 transformations happening to it:

  1. There is a color(blue)2 being added directly to the x, so it is f(x+color(blue)2), making it y=(x+color(blue)2)^2 --> this means that there will be a horizontal translation left of 2 units. In the graph, we take the original function and shift it left 2 units:
    graph{(x+2)^2 [-10, 10, -5, 5]}
  2. There is a negative sign color(red)- outside of the f(x+2), making it y=color(red)-(x+color(blue)2)^2 --> this means that there will be a reflection over the x-axis. In the graph, we take this shifted function and "flip" it over the x-axis:
    graph{-(x+2)^2 [-10, 10, -5, 5]}
  3. Finally, there is a color(green)2 being subtracted to the whole function, so color(red)-f(x+color(blue)2)-color(green)2. In the graph, this means that the shifted function needs to be shifted two units down:
    graph{-(x+2)^2-2 [-10, 10, -5, 5]}