How do you write the standard form of a line given (1, 5), m = -3?

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Answer 1 · 2017-08-18T05:54:19

$y = - 3 x + 8$ $y = -3x+8$

$3 x + y = 8 \leftarrow$ $3x+y =8" "larr$ standard form

Use the point-slope formula: $y - y_{1} = m (x - x_{1})$ $y-y_1 = m(x-x_1)$

We have $(1, 5) = (x_{1}, y_{1}) and m = - 3$ $(1,5) = (x_1,y_1) and m =-3$

$y - 5 = - 3 (x - 1)$ $y-5=-3(x-1)$

$y - 5 = - 3 x + 3$ $y-5 =-3x+3$

$y = - 3 x + 3 + 5$ $y = -3x+3+5$

$y = - 3 x + 8 \leftarrow y$ $y = -3x+8" "larr y$ -intercept/gradient form.

$3 x + y = 8 \leftarrow$ $3x+y =8" "larr$ standard form

$3 x + y - 8 = 0 \leftarrow$ $3x+y-8=0" "larr$ general form

I hope that helps!