How do you simplify #(n^3)^3*2n^-1# and write it using only positive exponents?

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Answer 1 · 2017-09-17T16:33:24

#2 n^(8)#

We have: #(n^(3))^(3) cdot 2 n^(- 1)#

Using the laws of exponents:

#= n^(9) cdot 2 n^(- 1)#

#= 2 cdot n^(9) cdot n^(- 1)#

#= 2 cdot n^(9 + (- 1))#

#= 2 cdot n^(9 - 1)#

#= 2 cdot n^(8)#

#= 2 n^(8)#