How do you simplify $(n^3)^3*2n^-1$ and write it using only positive exponents?

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Answer 1 · 2017-09-17T16:33:24

$2 n^(8)$

We have: $(n^(3))^(3) cdot 2 n^(- 1)$

Using the laws of exponents:

$= n^(9) cdot 2 n^(- 1)$

$= 2 cdot n^(9) cdot n^(- 1)$

$= 2 cdot n^(9 + (- 1))$

$= 2 cdot n^(9 - 1)$

$= 2 cdot n^(8)$

$= 2 n^(8)$

How do you simplify (n^3)^3*2n^-1(n^3)^3*2n^-1 and write it using only positive exponents?