How do you find the restrictions of $3/(x-4)-7$ ?

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Answer 1 · 2017-09-28T14:09:16

$x!= 4$

if $x=4$ , you will have $3/0 -7$ which is undefined.
So, we exclude that from the domain of x.

Answer 2 · 2017-09-28T14:09:19

See a solution process below:

We cannot divide by $0$ .

Therefore:

$x - 4 != 0$

Or

$x - 4 + color(red)(4) != 0 + color(red)(4)$

$x - 0 != 4$

$x != 4$

How do you find the restrictions of 3/(x-4)-73/(x-4)-7?