How do you find the derivative of #(x-3)/(2x+1)#?
2 Answers
Oct 5, 2017
Explanation:
#"differentiate using the "color(blue)"quotient rule"#
#"given "f(x)=(g(x))/(h(x))" then"#
#f'(x)=(h(x)g'(x)-g(x)h'(x))/(h(x))^2larr" quotient rule"#
#g(x)=x-3rArrg'(x)=1#
#h(x)=2x+1rArrh'(x)=2#
#rArrf'(x)=((2x+1)-2(x-3))/(2x+1)^2#
#color(white)(rArrf'(x))=7/(2x+1)^2#
Oct 5, 2017
Explanation:
Quotient rule:
In this function,
So plugging that in gets: