Question

What is the derivative of `y = [(x-2)/k]^(1/2)` where k is a constant?

Answer 1

Look below.

Explanation:

where `k!=0`

`dy/dx=1/2[(x-2)/k]^(-1/2)*d/dx((x-2)/k)`

`=1/2[(x-2)/k]^(-1/2)*(1/k)`

`=1/(2sqrt(k(x-2))`