How do you simplify $(3a^4b^2)^3$ ?

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Answer 1 · 2017-10-24T11:01:53

$27a^12b^6$

Move the $3$ inside by simply multiplying every power by $3$ .

$(3a^4b^2)^3 = (3^1a^4b^2)^3$

$= (3^(1xx3)a^(4xx3)b^(2xx3))$

$= 3^3a^12b^6$

You can calculate $3^3$ straight away, because

$3^3 = 3xx3xx3 = (3xx3)xx3 = 9xx3 = 27$

so

$(3a^4b^2)^3 = 27a^12b^6$

How do you simplify (3a^4b^2)^3(3a^4b^2)^3?