How do you write the point slope form of the equation given (4,-5) and m=6?

2 Answers
Nov 15, 2017

#y=6x-29#
graph{y=6x-29 [-10, 10, -5, 5]}

Explanation:

The formula to find the equation is #y=mx+b#

Since we know that #m=6#, the equation we have so far would be #y=6x+b#.

Now, we will find #b#.

Plug in #(4, -5)# where #x=4# and #y=-5#

#-5=6*4+b#

Switch sides:
#6*4+b=-5#

Multiply the numbers:
#24+b=-5#

Subtract #24# from both sides:
#24+bcolor(red)-color(red)24=-5color(red)-color(red)24#

Simplify:
#b=-29#

Therefore, the whole equation is:
#y=6x-29#.

Nov 15, 2017

#y+5=6(x-4)#

Explanation:

Remember that the point-slope form equation looks like this:

#y-k=m(x-h)#

Where #h# and #k# represents a point on the line and #m# is the slope.

The point should have the coordinates like this: #(h,k)#

What we have to do is substitute the values in like so:

#y-k=m(x-h)#
#y-(-5)=6(x-4)#
So the answer must be:
#y+5=6(x-4)#

Sweeeeet