How do you convert $(6, - \frac{π}{5})$ $(6,-pi/5)$ into rectangular coordinates?

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How do you convert $(6, - \frac{π}{5})$ $(6,-pi/5)$ into rectangular coordinates?

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Answer 1 · 2017-11-18T00:45:32

$\approx (4.854, - 3.527)$ $approx (4.854, -3.527)$

Explanation:

In general to convert the polar coordinate $(r, θ)$ $(r, theta)$ into rectangular coordinates, you just do $(r cos θ, r sin θ)$ $(rcostheta, rsintheta)$ .

In the case of $(6, - \frac{π}{5})$ $(6, -pi/5)$ , this would be
$(6 cos (- \frac{π}{5}), 6 sin (- \frac{π}{5})) \approx$ $(6cos(-pi/5), 6sin(-pi/5)) approx$ (4.854, -3.527)#

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How do you convert $(6, - \frac{π}{5})$ $(6,-pi/5)$ into rectangular coordinates?

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How do you convert (6,−π5)(6,-pi/5) into rectangular coordinates?

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How do you convert $(6, - \frac{π}{5})$ $(6,-pi/5)$ into rectangular coordinates?