What is the derivative of $π cos (\frac{π t}{6})$ $picos((pit)/6)$ ?

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What is the derivative of $π cos (\frac{π t}{6})$ $picos((pit)/6)$ ?

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Answer 1 · 2017-11-19T00:00:27

$\frac{- π^{2} sin (\frac{π t}{6})}{6}$ $(-pi^2sin((pit)/6))/6$

Explanation:

Assuming we are differentiating with respect to $t$ $t$ ,
Because $π$ $pi$ is a constant, only differentiate cos, then differentiate what's inside the bracket!
$π \times - sin (\frac{π t}{6}) \times (\frac{π}{6})$ $pi xx -sin((pit)/6) xx (pi/6)$
= $\frac{- π^{2} sin (\frac{π t}{6})}{6}$ $(-pi^2sin((pit)/6))/6$

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What is the derivative of $π cos (\frac{π t}{6})$ $picos((pit)/6)$ ?

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What is the derivative of picos((pit)/6)πcos(πt6)picos((pit)/6)?

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Explanation:

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What is the derivative of $π cos (\frac{π t}{6})$ $picos((pit)/6)$ ?