What is the vertex form of #y= 6x^2-9x+3 #?
2 Answers
Explanation:
To complete the square of the equation, first take out the 6:
Then do the bit in the brackets:
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#
#"to obtain this form use the method of"#
#color(blue)"completing the square"#
#• " the coefficient of the "x^2" term must be 1"#
#rArry=6(x^2-3/2x)+3#
#• " add/subtract "(1/2"coefficient of x-term")^2" to"#
#x^2-3/2x#
#rArry=6(x^2+2(-3/4)xcolor(red)(+9/16)color(red)(-9/16))+3#
#rArry=6(x-3/4)^2-27/8+3#
#rArry=6(x-3/4)^2-3/8larrcolor(red)"in vertex form"#