A projectile is shot from the ground at a velocity of $15 \frac{m}{s}$ $15 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?

Question

A projectile is shot from the ground at a velocity of $15 \frac{m}{s}$ $15 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?

2 Answers

Impact of this question

2059 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-17T12:51:24

The time is $= 1.53 s$ $=1.53s$

Explanation:

Resolving in the vertical direction ${↑ ⏐ ⏐}^{+}$ $uarr^+$

The initial velocity is $u_{0} = 15 sin (\frac{1}{6} π) m s^{- 1}$ $u_0=15sin(1/6pi)ms^-1$

The time to reach the greatest height is $= t s$ $=ts$

Applying the equation of motion

$v = u + a t = u - g t$ $v=u+at=u- g t$

The time is $t = \frac{v - u}{- g} = \frac{0 - 15 sin (\frac{1}{6} π)}{- 9.8} = 0.765 s$ $t=(v-u)/(-g)=(0-15sin(1/6pi))/(-9.8)=0.765s$

The time taken to land is twice the time to reach the greatest height

$T = 2 t = 2 \cdot 0.765 = 1.53 s$ $T=2t=2*0.765=1.53s$

Answer 2 · 2017-12-17T12:59:55

$1.531 s$ $1.531 s$

Explanation:

Here you actually asked about the wandering period of the projectile.

The initial velocity, $v_{0} = 15 m s^{- 1}$ $v_0=15 ms^(-1)$

**The throwing angle of the projectile,θ= $\frac{π}{6} = 30 \circ$ $pi/6=30@$ **
$S u p p o s e,$ $Suppose,$
The wandering period of the projectile, $T = ?$ $color(red)(T)=?$

we know that,
$T = \frac{2 v_{0} sin θ}{g} = \frac{2 \times 15 m s^{- 1} \times sin 30 \circ}{9.8 m s^{- 2}} = 1.531 s$ $T=color(blue)((2v_0sintheta)/g)=(2xx15ms^(-1)xxsin30@)/(9.8 ms^(-2))=1.531 s$ $(A n s .)$ $color(red)((Ans.)$

Science

Math

Humanities

... and beyond

A projectile is shot from the ground at a velocity of $15 \frac{m}{s}$ $15 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

A projectile is shot from the ground at a velocity of 15 m/s15ms15 m/s at an angle of pi/6π6pi/6. How long will it take for the projectile to land?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

A projectile is shot from the ground at a velocity of $15 \frac{m}{s}$ $15 m/s$ at an angle of $\frac{π}{6}$ $pi/6$ . How long will it take for the projectile to land?