How do you divide #( 2x^4 - 5x^3 - x^2 - 17x - 15 )/(x^2 - 2 )#?

1 Answer
kubik98
Dec 21, 2017

#(2x^4−5x^3−x^2−17x−15)/(x^2−2)=2x^2-5x+3-(27x+9)/(x^2-2)#

Explanation:

#(2x^4−5x^3−x^2−17x−15)-:(x^2−2)=2x^2-5x+3#
#color(white)(.)(2x^4+0-4x^2)/#
#color(white)(.....)-5x^3+3x^2-17x-15#
#color(white)(.....)(-5x^3+0+10x)/#
#color(white)(...................)3x^2-27x-15#
#color(white)(...................)(3x^2+0-6)/#
#color(white)(.........................)-27x-9#

#(2x^4−5x^3−x^2−17x−15)/(x^2−2)=2x^2-5x+3-(27x+9)/(x^2-2)#

Related questions
See all questions in Division of Polynomials
Impact of this question
1522 views around the world
You can reuse this answer
Creative Commons License