How do you divide ( 2x^4 - 5x^3 - x^2 - 17x - 15 )/(x^2 - 2 )2x4−5x3−x2−17x−15x2−2?

1 Answer
kubik98
Dec 21, 2017

(2x^4−5x^3−x^2−17x−15)/(x^2−2)=2x^2-5x+3-(27x+9)/(x^2-2)2x4−5x3−x2−17x−15x2−2=2x2−5x+3−27x+9x2−2

Explanation:

(2x^4−5x^3−x^2−17x−15)-:(x^2−2)=2x^2-5x+3(2x4−5x3−x2−17x−15)÷(x2−2)=2x2−5x+3
color(white)(.)(2x^4+0-4x^2)/.2x4+0−4x2
color(white)(.....)-5x^3+3x^2-17x-15
color(white)(.....)(-5x^3+0+10x)/
color(white)(...................)3x^2-27x-15
color(white)(...................)(3x^2+0-6)/
color(white)(.........................)-27x-9

(2x^4−5x^3−x^2−17x−15)/(x^2−2)=2x^2-5x+3-(27x+9)/(x^2-2)

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