An object's two dimensional velocity is given by v(t) = ( t^2 +2t , cospit - 3t )v(t)=(t2+2t,cosπt−3t). What is the object's rate and direction of acceleration at t=1 t=1?
1 Answer
Dec 25, 2017
Explanation:
a(1) = (4, -3)
The magnitude of the acceleration is
The direction of the acceleration is determined from
or