How do you write $f (x) = - 2 x^{2} + 6 x + 2$ $f(x)= -2x^2+6x+2$ in vertex form?

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How do you write $f (x) = - 2 x^{2} + 6 x + 2$ $f(x)= -2x^2+6x+2$ in vertex form?

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Answer 1 · 2017-12-30T10:24:05

$- 2 {(x - \frac{3}{2})}^{2} + \frac{13}{2}$ $- 2 ( x - 3/2 )^2 + 13/2$

Explanation:

$- 2 x^{2} + 6 x + 2$ $- 2x^2 + 6x + 2$
$= - 2 (x^{2} - 3 x) + 2$ $= - 2 (x^2 - 3x) + 2$
$= - 2 (x^{2} - 2 \cdot \frac{3}{2} \cdot x + {(\frac{3}{2})}^{2} - {(\frac{3}{2})}^{2}) + 2$ $= - 2 (x^2 - 2 * 3/2 * x + (3/2)^2 - (3/2)^2) + 2$
$= - 2 {(x - \frac{3}{2})}^{2} + 2 + \frac{9}{2}$ $= - 2 (x -3/2)^2 + 2 + 9/2$
$= - 2 {(x - \frac{3}{2})}^{2} + \frac{13}{2}$ $= - 2 (x - 3/2)^2 + 13/2$

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How do you write $f (x) = - 2 x^{2} + 6 x + 2$ $f(x)= -2x^2+6x+2$ in vertex form?

1 Answer

Explanation:

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Science

Math

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How do you write f(x)= -2x^2+6x+2f(x)=−2x2+6x+2f(x)= -2x^2+6x+2 in vertex form?

1 Answer

Explanation:

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How do you write $f (x) = - 2 x^{2} + 6 x + 2$ $f(x)= -2x^2+6x+2$ in vertex form?