Question

If a projectile is shot at an angle of `pi/12` and at a velocity of `14 m/s`, when will it reach its maximum height??

Answer 1

`0.36 s`

Explanation:

Clearly,here the projectile will go upwards due to its vertical component of velocity,which is `14 sin (pi/12)` i.e `3.62 m/s` (considering the given angle was w.r.t the ground)

So,now we can use `v=u-at` (all the symbols are bearing their conventional meaning)

Here,`v=0,u=3.62 ,a=g` and `t` is the time in which it will reach the highest point.

So,we get,`t=0.36 s`