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Answer 1 · 2018-01-26T06:46:35

$(sqrt85, tan^-1 (9/3))$

Given the complex number,

$2+9i$

we know that the modulus is $r=sqrt(x^2+y^2)$ and the argument is $theta$ = $tan^-1(y/x)$

Here

$y = 9$ and $x = 2$

so

$r=sqrt(2^2+9^2) = sqrt(85)$

$theta=tan^-1 (9/2)$

The polar form of the complex number is $(sqrt85, tan^-1 (9/3))$