How do you divide $\frac{- x^{4} + 6 x^{3} - 12 x^{2} - 7 x - 7}{x - 2}$ $(-x^4+6x^3-12x^2-7x-7)/(x-2)$ ?

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How do you divide $\frac{- x^{4} + 6 x^{3} - 12 x^{2} - 7 x - 7}{x - 2}$ $(-x^4+6x^3-12x^2-7x-7)/(x-2)$ ?

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Answer 1 · 2018-01-27T01:15:33

To simplify the given equation, divide the number values and subtract the variable's exponent. (see explanation)

Explanation:

$\frac{- x^{4} + 6 x^{3} - 12 x^{2} - 7 x - 7}{x - 2}$ $(-x^4+6x^3-12x^2-7x-7)/(x-2)$
$= (- x^{3} - 3 x^{2} + 6 x) + (\frac{7}{2}) + (\frac{7}{2})$ $=(-x^3-3x^2+6x)+(7/2)+(7/2)$
$= - x^{3} - 3 x^{2} + 6 x + 7$ $=-x^3-3x^2+6x+7$

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How do you divide $\frac{- x^{4} + 6 x^{3} - 12 x^{2} - 7 x - 7}{x - 2}$ $(-x^4+6x^3-12x^2-7x-7)/(x-2)$ ?

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Explanation:

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How do you divide (-x^4+6x^3-12x^2-7x-7)/(x-2) −x4+6x3−12x2−7x−7x−2(-x^4+6x^3-12x^2-7x-7)/(x-2) ?

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Explanation:

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How do you divide $\frac{- x^{4} + 6 x^{3} - 12 x^{2} - 7 x - 7}{x - 2}$ $(-x^4+6x^3-12x^2-7x-7)/(x-2)$ ?