How do you simplify the expression $(x+6)/(x^2-4) - (x-3)/(x+2) + (x-3)/(x-2)$ ?

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Answer 1 · 2018-03-02T19:24:18

$(5x-6)/[(x+2)(x-2)]= (5x-6)/[(x^2+4)$

Rewrite $x^2-4$ as $x^2-2^2$

$(x+6)/(x^2−2^2)-(x−3)/(x+2)+(x−3)/(x−2)$

Since $color(red)(a^2-b^2=(a+b) (a-b),$

$= (x+6)/color(red)[(x+2)(x-2)]-(x-3)/(x+2)+(x-3)/(x-2)$

Taking the LCM

$= [(x+6)-(x-3)(x-2)+(x-3)(x+2)]/[(x+2)(x-2)]$

Expand

$=[x+6-x^2+2x+3x-6+x^2+2x-3x-6]/[(x+2)(x-2)]$

Collect like terms

$= [(x+2x+3x+2x-3x)+(6-6-6)+(-x^2+x)]/[(x+2)(x-2)]$

Simplify

$= (5x-6)/[(x+2)(x-2)] = (5x-6)/[(x^2+4)$

~Hope this helps! :)

How do you simplify the expression (x+6)/(x^2-4) - (x-3)/(x+2) + (x-3)/(x-2)(x+6)/(x^2-4) - (x-3)/(x+2) + (x-3)/(x-2)?