Question

How do you solve `-8x + 10= - 6x + 20`?

Answer 1

`x=-5`

Explanation:

We can start by adding `8x` to both sides of the equation. We get:

`10=2x+20`

We can subtract `20` from both sides to get:

`-10=2x`

Switching the sides...

`2x=-10`

We can divide both sides by `2` to get:

`x=-5`

Answer 2

`x=-5`

Explanation:

As with any equation, we always want `x` on one side. Therefore we would either `+8x` or `+6x` to cancel out one of the `x's` on any side, depending on what you choose to add. As adding `8x` would make the `-6x` positive I will choose to `+8x`.

`-8x+10=-6x+20 -> 10=2x+20`

As want `x` on its own, we `-20` from both sides, as this would cancel the `+20` on the side with the `x`, getting rid of it. Always remember, what you do to one side, you must do to the other.

`10=2x+20 -> 2x=-10`

To solve an equation like this, we always divide the value by the value of `x's`.

`x=-10/2=-5`

`therefore` `x=-5`