How do you find all zeros of $h (t) = t^{2} - 6 t + 9$ $h(t)=t^2-6t+9$ ?

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How do you find all zeros of $h (t) = t^{2} - 6 t + 9$ $h(t)=t^2-6t+9$ ?

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Answer 1 · 2018-03-05T06:09:48

3, that is the only root of $h (t)$ $h(t)$ .

Explanation:

$h (t)$ $h(t)$ is a quadratic in $t$ $t$ which is :
$h (t) = t^{2} - 6 t + 9$ $h(t)=t^2-6t+9$
to find its zeros we equate the function with 0.
$h (t) = 0 \Rightarrow t^{2} - 6 t + 9 = 0$ $h(t) = 0 => t^2-6t+9 = 0$

Now by splitting the middle term,
$\Rightarrow t^{2} - 3 t - 3 t + 9 = 0$ $=>t^2 -3t -3t +9= 0$
$\Rightarrow t (t - 3) - 3 (t - 3) = 0$ $=>t(t-3)-3(t-3) = 0$
$\Rightarrow (t - 3) (t - 3) = 0$ $=>(t-3)(t-3) = 0$

Hence the root is 3.

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How do you find all zeros of $h (t) = t^{2} - 6 t + 9$ $h(t)=t^2-6t+9$ ?

1 Answer

Explanation:

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How do you find all zeros of h(t)=t2−6t+9h(t)=t^2-6t+9?

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How do you find all zeros of $h (t) = t^{2} - 6 t + 9$ $h(t)=t^2-6t+9$ ?