How do you solve $x^2+4x-5=0$ ?

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Answer 1 · 2018-03-07T01:32:19

$x= -5 or +1$

First, factor this equation. Then, determine what two values add to equal to the middle term $(+4)$ and multiply to the last term $(-5)$ ,

$+5 and -1$

Plug it in the equation:

$(x+5)(x-1)$

and set equal to zero

$(x+5)(x-1)=0$

$x+5=0 => x=-5$

$x-1=0 => x=+1$

How do you solve x^2+4x-5=0 x^2+4x-5=0 ?