What is the equation of the line which passes through the points $(2, - 3)$ $(2, -3)$ and $(1, - 3)$ $(1, -3)$ ?

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Answer 1 · 2018-03-10T22:11:08

$y = - 3$ $y =-3$

Begin by finding the slope of the line using the formula

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2-y_1)/(x_2-x_1)$

For the points
$(2, - 3) and (1, - 3)$ $(2,-3) and (1,-3)$

$x_{1} = 2$ $x_1 = 2$
$x_{2} = - 3$ $x_2 = -3$
$x_{2} = 1$ $x_2 = 1$
$y_{2} = - 3$ $y_2=-3$

$m = \frac{- 3 - (- 3)}{1 - 2}$ $m = (-3-(-3))/(1-2)$

$m = \frac{0}{- 1}$ $m=0/-1$

$m = 0$ $m=0$

This equation is actually a horizontal line running through the y axis at $y = - 3$ $y=-3$

What is the equation of the line which passes through the points (2,−3)(2, -3) and (1,−3)(1, -3)?