Question

How do you write the equation of the circle with center at (6, –2) and diameter = 12?

Answer 1

`(x-6)^2+(y+2)^2=36`

Explanation:

Use the equation, `(x+x_1)^2+(y+y_1)^2=r^2`

Where

`x` = x-coordinate
`y` = y-coordinate
`r` = radius

Substitute the values in and change `+6` to `-6` and `-2` to `+2`

`(x-6)^2+(y+2)^2=36`