How do you simplify $- {(3 a^{6} b^{4})}^{3}$ $-(3a^6b^4)^3$ ?

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Answer 1 · 2018-03-18T21:19:43

$- 27 a^{18} b^{12}$ $-27a^18b^12$

$= - {(3 a^{6} b^{4})}^{3}$ $color(white)=-(3a^6b^4)^3$

$= - (3 \times 3 \times 3) \cdot a^{18} \cdot b^{12}$ $= -(3xx3xx3)*a^18*b^12$

$= - 27 a^{18} \cdot b^{12}$ $=-27a^18*b^12$

the rules of indices say that you will multiply.

How do you simplify −(3a6b4)3-(3a^6b^4)^3?