Question

How do you write the rectangular coordinates for the point: `(6, 3/2 pi)`?

Answer 1

`(-3,3sqrt(3))`

Explanation:

For given coordinates `(r,theta)`, `(r,theta)to(x,y)=>(rcostheta,rsintheta)`

`r=6`
`theta=(2pi)/3`

`(6,(2pi)/3)to(x,y)=>(6cos((2pi)/3),6sin((2pi)/3))-=(-3,3sqrt(3))`