What is the equation of the line passing through the point (19, 23) and parallel to the line y= 37x + 29?

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What is the equation of the line passing through the point (19, 23) and parallel to the line y= 37x + 29?

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Answer 1 · 2018-03-23T18:21:46

$y = 37 x - 680$ $y = 37x - 680$

Explanation:

Since the y= 37x + 29 's slope is 37, thus our line is also has the same slope.

m1=m2= 37

using point slope equation, y-y1 = m(x-x1)

$y - y 1 = m (x - x 1)$ $y - y 1 = m (x - x 1 )$

$y - 23 = 37 (x - 19)$ $y - 23 = 37 (x - 19 )$

$y - 23 = 37 x - 703$ $y - 23 = 37x - 703$

$y = 37 x - 703 + 23$ $y = 37x - 703+23$

$y = 37 x - 680$ $y = 37x - 680$

Answer 2 · 2018-03-23T18:52:57

$y = 37 x - 680$ $y=37x-680$

Explanation:

We know that, if the slope of the line $l_{1}$ $l_1$ is $m_{1}$ $m_1$ and the slope of the line $l_{2}$ $l_2$ is $m_{2}$ $m_2$ then $l_{1} / / l_{2} \Leftrightarrow m_{1} = m_{2}$ $color(red)(l_1////l_2<=>m_1=m_2$ (parallel lines)

The line $l$ $l$ passes through $(19, 23)$ $(19,23)$ .

Line $l$ $l$ is parallel to $y = 37 x + 29$ $y=37x+29$

Comparing with $y = m x + c \Rightarrow m = 37$ $y=mx+c=>m=37$

So, the slope of the line $l$ $l$ is $m = 37$ $m=37$

The equation of line $l$ $l$ passes through $(x_{1}, y_{1}) and$ $(x_1,y_1) and$ has

slope m is

$y - y_{1} = m (x - x_{1})$ $color(red)(y-y_1=m(x-x_1)$ .,where, $(x_{1}, y_{1}) = (19, 23) and m = 37$ $( x_1,y_1)=(19,23) and m=37$

$:.y-23=37(x-19)$

$=>y-23=37x-703$

$=>y=37x-680$

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What is the equation of the line passing through the point (19, 23) and parallel to the line y= 37x + 29?

2 Answers

Explanation:

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