Question

How do you simplify `5/(x+3) - 2/(x-1)`?

Answer 1

`(3x-11)/((x+3)(x-1))`
Where `x!=-3 or 1`

Explanation:

`(3x-11)/((x+3)(x-1))`
Where `x!=-3 or 1`
The reason x can't be -3 or 1 is because if this happens the denominator will become `0` and anything with denominator `0` becomes undefined.

Answer 2

The given question states :
`5/(x+3)-2/(x-1)`

So, processing further:
`rArr(5 xx( x-1)-2 xx( x+3))/((x+3) xx (x-1)`

`rArr((5x-5 )-(2x+6))/((x+3) ( x-1)`

`rArr(5x-5-2x-6)/((x+3)(x-1)`

`rArr(5x-2x -5-6)/((x+3)(x-1)`

`rArr(3x-11) /((x+3) (x-1))`

`rArr(3x-11) /(x^2-x+3x-3)`

`rArr(3x-11) /(x^2+2x-3)`

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