How do you simplify $\frac{3}{x} - \frac{2}{x + 1}$ $3/x - 2/(x+1)$ ?

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Answer 1 · 2018-03-25T05:50:31

$\frac{x + 3}{x^{2} + x}$ $(x+3)/(x^2+x)$

$\frac{3}{x} - \frac{2}{x + 1}$ $3/x - 2/(x+1)$

Make both terms of same denominator,

$\frac{3 (x + 1)}{x (x + 1)} - \frac{2 (x)}{(x + 1) (x)}$ $(3(x+1))/(x(x+1)) - (2(x))/((x+1)(x))$

Expand,

$\frac{3 x + 3}{x^{2} + x} - \frac{2 x}{x^{2} + x}$ $(3x+3)/(x^2+x)-(2x)/(x^2+x)$

Combine,

$\frac{x + 3}{x^{2} + x}$ $(x+3)/(x^2+x)$

Answer 2 · 2018-03-25T05:57:13

$\frac{x + 3}{x^{2} + x}$ $(x+3)/(x^2+x)$

$\frac{x + 3}{x^{2} + x}$ $(x+3)/(x^2+x)$

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