Question

How do you find `h(x)=f(x)+g(x)` given `f(x)=abs(x-3)` and `g(x)=4`?

Answer 1

`h(x)=x+1`

Explanation:

`h(x)=f(x)+g(x)`

`f(x)=|x-3|`

`g(x)=4`

`h(x)=|x-3|+4`

`h(x) = x-3+4`

`h(x)=x+1`