An object is thrown vertically from a height of #9 m# at # 6 m/s#. How long will it take for the object to hit the ground?
2 Answers
The time to hit the ground is
Explanation:
Resolve in the vertical direction
The initial velocity is
The acceleration due to gravity is
The distance is
Applying the equation of motion
Solving this quadratic equation in
The time to hit the ground is
graph{4.9x^2-6x-9 [-9.99, 10.02, -5, 4.995]}
First, calculate the time the object takes to reach the maximum height.
To calculate the time taken to reach the maximum height, you have the following info:
According to the first equation of motion,
Plug in the values:
or,
or,
To reach the same height from where it was thrown (i. e.,
Thus, time taken to go up and come down to the
Now, all you need is the time taken by the object to go down the last
For that,
Use the third equation to get:
Plug in the values;
Now, find the time using the first equation of motion:
Thus, total time,
hope that helped...Thanks for reading!!!