How do you solve the system of equations $5 x - 2 y = 12$ $5x - 2y = 12$ and $2 x - 3 y = 7$ $2x - 3y = 7$ ?

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Answer 1 · 2018-03-30T07:24:10

$x = 2$ $x=2$
$y = - 1$ $y=-1$

= $5 x - 2 y = 12$ $5x-2y=12$

Multiplying above equation with $2$ $2$

= $2 x - 3 y = 7$ $2x-3y=7$

Multiplying above equation with 5

Now subtracting both equations to cancel out $10 x$ $10x$

= $(10 x - 4 y = 24) - (10 x - 15 y = 35)$ $(10x-4y=24)-(10x-15y=35)$

= $11 y = - 11$ $11y=-11$

= $y = - 1$ $y=-1$

Now for $x$ $x$ put y=-41 in below equation

= $2 x - 3 y = 7$ $2x-3y=7$

= $2 x - 3 (- 1) = 7$ $2x-3(-1)=7$

= $2 x = 4$ $2x=4$

= $x = 2$ $x=2$

Hope this helps!

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How do you solve the system of equations 5x−2y=125x - 2y = 12 and 2x−3y=7 2x - 3y = 7?