How do you differentiate #y=sin^-1(-2x^2)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Timber Lin Apr 2, 2018 #(-4x)/sqrt(1-4x^4)# Explanation: #d/dx(arcsin(-2x^2))# #=1/sqrt(1-(-2x^2)^2)*d/dx(-2x^2)# (arcsin derivative and chain rule) #=1/sqrt(1-4x^4)*(-4x)# #=(-4x)/sqrt(1-4x^4)# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 2754 views around the world You can reuse this answer Creative Commons License