How do you find the derivative of #(e^(2x)-e^(-2x))/(e^(2x)+e^(-2x))#?

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Answer 1 · 2018-04-03T15:37:42

#2(1-(e^((2.x) - e^(-2.x)) /(e^(2.x) + e^(-2.x)))^2)#

isn't that just #tanh2x#?

and the derivative of #tanhx# = #1-(tanhx)^2#
you can find more about hyperbolic functions from this link
http://math2.org/math/derivatives/more/hyperbolics.htm

thus the derivative of
#tanh2x#

is

#2(1-(tanhx)^2)#

How do you find the derivative of #(e^(2*x)-e^(-2*x))/(e^(2*x)+e^(-2*x))#?