How do you solve (x+9)^"2/3"=4?

1 Answer
Apr 3, 2018

See below.

Explanation:

To solve this problem, we need to do something with that 2/3 power first.

Since the 2/3 encompasses an expression using addition, the power does not distribute. So we have to do a little manipulation:

(x+9)^(2/3)=4 => root(3)((x+9)^(2))=4

Now that we have that, we can start to simplify this a little.

Since the cube root encompasses the entirety of the left side, we can cube the whole thing to get rid of it.

color(blue)(Note:"What you do to one side, you must do to the other".

We should now have this:

root(3)((x+9)^(2))=4

=>(root(3)((x+9)^(2)))^3=4^3

=>(x+9)^2=64

From here we need to put the (x+9)^2 into standard form, and solve from there:

(x+9)^2=64

=>x^2+18x+81=64

=>x^2+18x+15=0

To solve this, we can use the quadratic formula, which is defined as:

-color(red)(b)+-sqrt(color(red)(b)^2-4color(blue)(a)color(green)(c))/(2color(blue)(a))

color(blue)(a=1) color(red)(b=18) color(green)(c=15)

=(-color(red)(18)+-sqrt(color(red)(18)^2-4(color(blue)(1))(color(green)(15))))/(2(color(blue)(1))

=-(18+-sqrt(324-60))/(2)

=(-18+-2sqrt(66))/2

=-9+-sqrt(66)

Hope this helped!