How do you write an equation in standard form for a line passing through (2, -3), m= -3.6?

1 Answer
Apr 8, 2018

18x + 5y = 21

Explanation:

The standard form of a linear equation is Ax + By = C.

Since we are given a slope and a point, the slope-intercept form of a linear equation will quickly provide us with an answer.

Recall that any (non-vertical) line can be written in the form y = mx + b, where m is our slope and b is our initial value. We find b by plugging in the provided point and slope:

y = mx + b
y = -3.6x + b
-3 = -3.6(2) + b
-3 = -7.2 + b
4.2 = b

Thus, our linear equation in slope-intercept form is y = -3.6x + 4.2. By moving our term containing x to the left-hand side of the equation, we obtain our equation in standard form:

y = -3.6x + 4.2
3.6x + y = 4.2

We can clean up our answer by multiplying through by 10 to remove our decimals, then simplifying.

3.6x + y = 4.2
36x + 10y = 42
18x + 5y = 21