How do you factor x^3 - 2x^2 - 35xx32x235x?

2 Answers
Apr 8, 2018

x(x-7)(x+5)x(x7)(x+5)

Explanation:

First, factor out the GCF (x)

x(x^2-2x-35) rarrx(x22x35) Now you can use several different methods to factor the x^2-2x-35x22x35. You can use the "big X" method, the quadratic formula, or graphing.

Here I'll use the "big X" method.

Quadratic equation form: ax^2+bx+cax2+bx+c

Big X method: find two numbers that multiply to a*cac, in this case -35 (1*-35135) and add up to bb, in this case -22.

-7*5=-3575=35

-7+5=-27+5=2

The two numbers are -7 and 5

x^2-2x-35x22x35 can be factored to (x-7)(x+5)(x7)(x+5)

x(x-7)(x+5)x(x7)(x+5)

Apr 8, 2018

xx(x-7x7)(x+5x+5)

Explanation:

you take the xx as a common factor to be:
xx(x^2-2x-35x22x35)=0
then factor out what's between the brackets:
xx(x-7x7)(x+5x+5)