How do you solve using the completing the square method #x^2 + 2x = 3 #?

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Answer 1 · 2018-04-09T13:09:36

#x=1#

Adding 1 on both sides
=#x^2+2x+1=3+1#

=#(x+1)^2=4#

Taking square root on both sides

=#sqrt((x+1)^2)=sqrt4#

=#x+1=+-2#

=#x=1# & #x=-3#

Check

=#(1)^2+2(1)=3#

=#3=3#

Also #(-3)^2+2(-3)=3#

=#3=3#

Hope it helps!