How do you write the equation $y = (x - 4) (x - 2)$ $y= (x-4)(x-2)$ in standard form?

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How do you write the equation $y = (x - 4) (x - 2)$ $y= (x-4)(x-2)$ in standard form?

1 Answer

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Answer 1 · 2018-04-11T14:27:24

$y = x^{2} - 6 x + 8$ $y=x^2-6x+8$

Explanation:

Just multiply each factor:
$(x - 4) (x - 2) = x \cdot x - 2 \cdot x - 4 \cdot x + 8 =$ $(x-4)(x-2)=x*x-2*x-4*x+8=$
$= x^{2} - (2 + 4) x + 8 =$ $=x^2-(2+4)x+8=$
$= x^{2} - 6 x + 8$ $=x^2-6x+8$

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How do you write the equation $y = (x - 4) (x - 2)$ $y= (x-4)(x-2)$ in standard form?

1 Answer

Explanation:

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How do you write the equation y=(x−4)(x−2)y= (x-4)(x-2) in standard form?

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How do you write the equation $y = (x - 4) (x - 2)$ $y= (x-4)(x-2)$ in standard form?