Question

How do you solve `x^2 + 3x - (7/4) = 0` by completing the square?

Answer 1

`x = -1.5+-2`

Explanation:

`x^2+3x−7/4=0`

`(x+3/2)^2 - (3/2)^2 - 7/4 = 0`

`(x+3/2)^2 - 9/4 - 7/4 = 0`

`(x+3/2)^2 - 16/4 = 0`

`(x+3/2)^2 = 4`

`x+3/2 = sqrt4`

`color(red)(x= -3/2+-2)`

`color(red)(x=0.5 or x = -3.5)`