What is $\frac{5}{2} x^{2} - \frac{3}{4} x + 1$ $5/2x^2-3/4x+1$ is subtracted from $\frac{3}{2} x^{2} - \frac{1}{4} x - 4$ $3/2x^2-1/4x-4$ ?

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What is $\frac{5}{2} x^{2} - \frac{3}{4} x + 1$ $5/2x^2-3/4x+1$ is subtracted from $\frac{3}{2} x^{2} - \frac{1}{4} x - 4$ $3/2x^2-1/4x-4$ ?

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Answer 1 · 2018-04-16T14:25:16

$(\frac{3}{2} x^{2} - \frac{1}{4} x - 4) - (\frac{5}{2} x^{2} - \frac{3}{4} x + 1)$ $(3/2x^2-1/4x-4) - (5/2x^2-3/4x+1)$

Explanation:

$(\frac{3}{2} x^{2} - \frac{1}{4} x - 4) - (\frac{5}{2} x^{2} - \frac{3}{4} x + 1) =$ $(3/2x^2-1/4x-4) - (5/2x^2-3/4x+1)=$
$= (\frac{3}{2} - \frac{5}{2}) \cdot x^{2} + (- \frac{1}{4} + \frac{3}{4}) x + (- 4 - 1) =$ $=(3/2 - 5/2)*x^2+(-1/4+3/4)x+(-4-1)=$
$= - \frac{2}{2} \cdot x^{2} + \frac{2}{4} \cdot x - 5 =$ $=-2/2*x^2+2/4*x-5=$
$= - x^{2} + \frac{1}{4} x - 5$ $=-x^2+1/4x-5$

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What is $\frac{5}{2} x^{2} - \frac{3}{4} x + 1$ $5/2x^2-3/4x+1$ is subtracted from $\frac{3}{2} x^{2} - \frac{1}{4} x - 4$ $3/2x^2-1/4x-4$ ?

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