What is #5/2x^2-3/4x+1# is subtracted from #3/2x^2-1/4x-4#? Algebra Polynomials and Factoring Addition and Subtraction of Polynomials 1 Answer AltairSafir Apr 16, 2018 #(3/2x^2-1/4x-4) - (5/2x^2-3/4x+1)# Explanation: #(3/2x^2-1/4x-4) - (5/2x^2-3/4x+1)=# #=(3/2 - 5/2)*x^2+(-1/4+3/4)x+(-4-1)=# #=-2/2*x^2+2/4*x-5=# #=-x^2+1/4x-5# Answer link Related questions How do you add two polynomials? How do you subtract two polynomials? How do you add and simplify #3x^2-4x+7# and #2x^3-4x^2-6x+5#? How do you subtract #5b^2-2a^2# from #4a^2-8ab-9b^2#? How do you simplify #(6.9a^2-2.3b^2+2ab)+(3.1a-2.5b^2+b)#? How do you simplify #(-t+15t^2)-(5t^2+2t-9)#? How do you subtract #(-5m^2-m)-(3m^2+4m-5)#? How do you add two polynomials if they don't have like terms? How do you simplify #(3a+4b)-(-6a-3b)#? How do you subtract #(x^2-8x+7)-(6x^2+7x-3)#? See all questions in Addition and Subtraction of Polynomials Impact of this question 3058 views around the world You can reuse this answer Creative Commons License