Question

What is the derivative of `f(t) = (t^2-2e^(3t-1) , t-e^t )`?

Answer 1

`f'(t)=2t-2(3)e^(3t-1),1-e^t`

Explanation:

`f(x)=(t^2-2e^(3t-1),t-e^t)`
first use the power rule for `t^2,t`
`f'(x)=2t^(2-1)-2dy/dt(3t-1)e^(3t-1),dy/dt(t)e^t`
then use the `dy/dx(e)^u=e^u (du)`
therefore the derivative is `f'(x)=2t-6e^(3t-1), 1-e^t`