How do you write the equation in slope intercept form given (10,-9);m=-2?

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Answer 1 · 2018-04-24T19:38:08

$y = - 2 x - 19$ $y =-2x-19$

Since we are provided the slope and a point on the line we can use the equation for point slope form of the equation of a line.

$y - y_{1} = m (x - x_{1})$ $y-y_1 =m(x-x_1)$

Where $m =$ $m=$ slope and the point is $(x_{1}, y_{1})$ $(x_1,y_1)$

For this situation $m = - 5$ $m=-5$ and a point of $(10, - 9)$ $(10,-9)$

$m = - 2$ $m=-2$
$x_{1} = 10$ $x_1=10$
$y_{1} = - 9$ $y_1=-9$

$y - y_{1} = m (x - x_{1})$ $y-y_1 =m(x-x_1)$

Plug in the values
$y - (- 9) = - 2 (x - 10)$ $y-(-9) =-2(x-10)$

Simplify the signs
$y + 9 = - 2 (x + 10)$ $y+9 =-2(x+10)$

Use distributive property to eliminate the parenthesis
$y + 9 = - 2 x - 20$ $y+9 =-2x-20$

Use the additive inverse to isolate the $y$ $y$ value
$y cancel(+9) cancel(-9) =-2x-10-9$

Simplify the common terms
$y =-2x-19$