How do you express $sin^2 theta - tan theta +sintheta$ in terms of $cos theta$ ?

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Answer 1 · 2018-04-24T19:57:46

$1-cos^2 (theta) - (sqrt(1-cos^2(theta)))/cos(theta)+\sqrt(1-cos(theta))$

Remember:
$sin^2(theta)+cos^2(theta)=1$
$tan(theta)=sin(theta)/cos(theta)$

$sin^2 theta - tan theta +sin theta=$

$=1-cos^2 (theta) - sin(theta)/cos(theta)+\sqrt(1-cos(theta))=$

$=1-cos^2 (theta) - (sqrt(1-cos^2(theta)))/cos(theta)+\sqrt(1-cos(theta))$

How do you express sin^2 theta - tan theta +sintheta sin^2 theta - tan theta +sintheta in terms of cos theta cos theta ?