The gas inside of a container exerts $15 P a$ $15 Pa$ of pressure and is at a temperature of $450^{o} K$ $450 ^o K$ . If the pressure in the container changes to $25 P a$ $25 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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The gas inside of a container exerts $15 P a$ $15 Pa$ of pressure and is at a temperature of $450^{o} K$ $450 ^o K$ . If the pressure in the container changes to $25 P a$ $25 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2018-04-25T13:18:02

$p_{1} = 15 P a$ $p_1=15 Pa$
$T_1=450°C$
$p_2=25 Pa$
$V="const.$

Explanation:

$(p_1 V_1)/T_1=(p_2 V_2)/(T_2)$
Considering $V="const." => V_1=V_2$ , it become
$(p_1)/T_1=(p_2)/(T_2)$
$T_2=p_2/p_1 T_2=(15 Pa)/(25 Pa)*(450+273)K= 434 K$

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The gas inside of a container exerts $15 P a$ $15 Pa$ of pressure and is at a temperature of $450^{o} K$ $450 ^o K$ . If the pressure in the container changes to $25 P a$ $25 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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The gas inside of a container exerts 15 Pa15Pa15 Pa of pressure and is at a temperature of 450 ^o K450oK450 ^o K. If the pressure in the container changes to 25 Pa25Pa25 Pa with no change in the container's volume, what is the new temperature of the gas?

1 Answer

Explanation:

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The gas inside of a container exerts $15 P a$ $15 Pa$ of pressure and is at a temperature of $450^{o} K$ $450 ^o K$ . If the pressure in the container changes to $25 P a$ $25 Pa$ with no change in the container's volume, what is the new temperature of the gas?